Algebra Lineal David C Lay Solucionario
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- Algebra Lineal David C Lay Solucionario E
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- Algebra Lineal David C Lay Solucionario De La
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- Solucionario Algebra Lineal David C Lay 3ra Edicion
Solution manual / Answer to Exercises for Linear Algebra and Its Applications Solucionario/ Respuesta a los ejercicios para Algebra Lineal y sus aplicaciones Edicion/Edition: Third / 3era Autor/author: David C. Lay LINK DE DESCARGA/LINK TO DOWNLOAD.
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7.1 SOLUTIONS
Notes: Students can profit by reviewing Section 5.3 (focusing on the Diagonalization Theorem) before working on this section. Theorems 1 and 2 and the calculations in Examples 2 and 3 are important for the sections that follow. Note that symmetric matrix means real symmetric matrix, because all matrices in the text have real entries, as mentioned at the beginning of this chapter. The exercises in this section have been constructed so that mastery of the Gram-Schmidt process is not needed.
Theorem 2 is easily proved for the 2 2 case:
If ,a b
Ac d
Algebra Lineal David C Lay Solucionario E
= then ( )2 21 ( ) 4 .2 a d a d b = + + If b = 0 there is nothing to prove. Otherwise, there are two distinct eigenvalues, so A must be diagonalizable.
In each case, an eigenvector for is .db
Algebra Lineal David C Lay Solucionario Con
1. Since 3 5
,5 7
TA A = = the matrix is symmetric.
2. Since 3 5
,5 3
TA A
= the matrix is not symmetric.
3. Since 2 2
,4 4
TA A = the matrix is not symmetric.
4. Since 0 8 38 0 2 ,3 2 0
TA A
= =
the matrix is symmetric.
5. Since 6 2 00 6 2 ,0 0 6
Algebra Lineal David C Lay Solucionario De La
Algebra Lineal David C Lay Solucionario Y
TA A
=
Algebra Lineal David C Lay Solucionario Da
the matrix is not symmetric.
Solucionario Algebra Lineal David C Lay 3ra Edicion
6. Since A is not a square matrix TA A and the matrix is not symmetric.